Momentum & Impulse Work Day

OPENING QUESTION: A 2500 kg SUV is heading for a solid brick wall. If the airbag system exerts a maximum force 5010 N of force on the 71 kg driver, how much time will they experience that max force?

LEARNING TARGET:

I will be able to solve intermediate/advanced problems during today's class.

I will be able to solve intermediate/advanced impulse problems during today's class.

WORDS O' THE DAY:

  • momentum (p=mv)
  • impulse (∆p, mvf - mvi, or F∆t)
  • perfectly elastic collision - objects bounce off each other without ANY loss of anything (it's PERFECT)
  • inelastic collision - Objects STICK together

CALENDAR:

Lab Reports are Due looking Good and Standing Tall, Tomorrow (Friday, January 12th)

FORMULAE OBJECTUS:

p=mv

J = F∆t = ∆p = pf - pi = m(vf - vi)

m1iv1i + m2iv2i = m1fv1f + m2fv2f    (perfectly elastic)

m1iv1i + m2iv2i = (m1 + m2)vf      (inelastic) notice how we combine the masses

WORK O' THE DAY:

I will model the solution of the pencil problem. There is some VERY good learning to be had here not in the answer itself, but in the solution. Unlike most of the problems we've worked on this year, this problem requires us to break it into parts and solve one part and then work backwards. In otherwords, you have to lay out the problem, realize there is NO way to do it one step then evaluate the 2nd part of the problem and see what you can do there.... This is very definitely advanced problem solving!

If you'd like to dive into the last nasty problem, please do. Please DO NOT, however, if you struggled a fair bit on the pencil problem.

Consider the following:

A .126 kg ball is moving to the right at 2.38 m/s and it collides with a .675 kg ball moving to the left at .0995 m/s. If the final velocity of the 1st object is -1.80 m/s, what is the final velocity of the second object?

What additional information is required in order to complete that problem?

Do it! (Full Wolgemuthians as ALWAYS)

 

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